+738 hi guest!
we can start off by finding the y-coordinate which is (0,3),so that means that b=3.
next we can find the slope by using \(\dfrac{y_2-y_1}{x_2-x_1}\), and we can use (-1,0) and (0,3).
This would equal \(\dfrac{3-0}{0-(-1)}=\dfrac{3}{1}=3\).
so the answer is \(\boxed{y=3x+3}.\)
+169 Hmm
Khan Academy stuff I see
Although someone has given you the answer already, you shouldn't go right to that. Let's work through this.
The equation for a line is \(y=mx+b\), where \(m\) is the slope and \(b\) is the y-intercept.
Here, we see that \(3\) is obviously the intercept, but what is the slope? Well, to find it, we can get a set of clean points, and then apply the formula \(slope=\frac{\text{change in y}}{\text{change in x}}\). Here, we see that for every \(1\) unit across, it goes \(3\) units upwards. Using our formula, we get \(\frac{3}{1}=3\) as our slope, so our answer is \(\boxed{y=3x+3}\)
