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avatar+1146 

i am unsure how i would graph this

 Feb 11, 2019
 #1
avatar+18957 
+1

These are both equations of lines, with a common point at    3,-6      extend the blue line to the left.......and starting at the far right blue dot, extend the line through the red dots down and to the right

 

 Feb 12, 2019
 #2
avatar+1146 
0

the points without whole numbers I cannot graph . this is the only space I have it doesnt let me choose middle points.

jjennylove  Feb 12, 2019
 #3
avatar+18957 
0

Then just plot the whole numbers in the list.....and connect the dots as I explained....the lines will be the same....GLuck !

ElectricPavlov  Feb 12, 2019
 #4
avatar+1146 
0

wouldnt it be marked as incorrect if I do need plot all the points?  indecision

jjennylove  Feb 12, 2019
 #5
avatar+18957 
+1

SInce they are lines , you only need two points to draw each one....just make sure ONE of the points for both lines is the common point

3,-6

ElectricPavlov  Feb 12, 2019
 #9
avatar+1146 
0

Thank you smiley

jjennylove  Feb 12, 2019
 #6
avatar+103120 
+2

g(x) =  -2x ,  x ≥3

 

Let's just pick two x values ≥ 3   and stick them into the function

 

When x = 3,  y = -6.....so....(3, -6) is on the graph

When x = 4, y = -8.....so.....(4, -8) is on the graph

Plot  (3, -6)

Then...plot (4, -8).....draw a ray startting at (3, 6) and extend it through (4, -8)

 

 

g(x) = -(1/3)X - 5,  x ≤3

Again..let's pick x = 3   and put it into the function....and we have (-1/3)(3) - 5 = -1 - 5  = -6

So....the point (3, -6) is on the graph

Now.....pick anoher x value < 3.......0 is good

So   (-1/3)(0) - 5 =  -5

So (0, -5) is on this graph

Draw a ray from (-3, 6) through (0, -5)

 

The graph will look like this :

 

 

 

 

 

Of course...the lines (rays) will have "arrows" at their ends  

 

 

cool cool cool

 Feb 12, 2019
 #7
avatar+18957 
+1

....and now I learned another graphing tool/ method in Desmos ....Thanx  Chris !

ElectricPavlov  Feb 12, 2019
 #8
avatar+1146 
+1

Thank you for going indepth about how I would go so forth in solving. I was confused about it but with your explaination t\it all makes sense now thank you!smiley

jjennylove  Feb 12, 2019

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