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If two numbers will be randomly chosen without replacement from {3,4,5,6} , what is the probability that their product will be a multiple of 9? Express your answer as a common fraction.

 Nov 15, 2018
 #1
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\(\text{There are a total of }\dbinom{4}{2}=6 \text{ pairs} \\ (3,6) \text{ is the only pair whose product is a multiple of }9\\ \text{So }p=\dfrac 1 6\)

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 Nov 15, 2018
 #2
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Thank you, I appreciate it.

 Nov 15, 2018

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