If two numbers will be randomly chosen without replacement from {3,4,5,6} , what is the probability that their product will be a multiple of 9? Express your answer as a common fraction.
\(\text{There are a total of }\dbinom{4}{2}=6 \text{ pairs} \\ (3,6) \text{ is the only pair whose product is a multiple of }9\\ \text{So }p=\dfrac 1 6\)
+283 
