\(x^2 + bx + 9\) If has two non-real roots, find all possible values of \(b\). Express your answer in interval notation.

Thanks, I do not know how to solve this problem.

IIf we have non-real roots, the discriminant must be < 0

In the form

ax^2 + bx + c = 0

The discriminant is b^2 - 4ac

So b = b a = 1 and c = 9 ... so.....

b^2 - 4 (1) (9) < 0

b^2 - 36 < 0

b^2 < 36

The interval that makes this true is

-6 < b < 6