\(x^2 + bx + 9\) If has two non-real roots, find all possible values of \(b\). Express your answer in interval notation.
Thanks, I do not know how to solve this problem.
IIf we have non-real roots, the discriminant must be < 0
In the form
ax^2 + bx + c = 0
The discriminant is b^2 - 4ac
So b = b a = 1 and c = 9 ... so.....
b^2 - 4 (1) (9) < 0
b^2 - 36 < 0
b^2 < 36
The interval that makes this true is
-6 < b < 6