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The graph of y=ax^2+bx+c passes through points (0,5)$, $(1,10), and (2,19). Find a+b+c

 Jun 6, 2020
 #1
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When x = 0     y = 5

 

5 = a(0^2) + b(0) + c     so   c = 5

 

when x = 1    y = 10

 

10 = a(1^2) + b(1) + 5       or      a + b -5 = 0

 

when x = 2    y= 19

 

19 = a(4) + 2b  + 5       or         4a   + 2b  - 14 = 0     

                     you know 'c' and now you have two equations in red that you can use to find 'a' and 'b'

 Jun 6, 2020

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