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For what value of x does \(128^{x+2} = \left(\frac{1}{64}\right)^{x}\)? Express your answer as a common fraction.

 Jun 21, 2020
 #1
avatar+26870 
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128  = 27

1/64  = 2-6

 

(27)x+2  = (2-6)x     Equate the exponents

7x+14= -6x

x = -14/13

 Jun 21, 2020
 #2
avatar+793 
-1

Thank you so much!

AnimalMaster  Jun 21, 2020

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