For what value of x does \(128^{x+2} = \left(\frac{1}{64}\right)^{x}\)? Express your answer as a common fraction.
128 = 27
1/64 = 2-6
(27)x+2 = (2-6)x Equate the exponents
7x+14= -6x
x = -14/13
Thank you so much!
+865 
+36916 
