Two buildings are 200m apart. From a point midway between them, the angles of elevation to the top of each building are 12o and 9o respectively. To the nearest tenth, how much taller is one building compared to the other?

Guest Jul 5, 2020

#1**+1 **

I think that is supposed to be 12^{o }and 9 ^{o}

For one building tan 9 = height_{1} / 100

for the other building tan 12 = height_{2 }/100 Now you should be able to find their heights and the difference.....

ElectricPavlov Jul 5, 2020