+0  
 
0
654
3
avatar+546 

fifth root(32y^10)

 Jul 9, 2014

Best Answer 

 #2
avatar+118680 
+10

Almost but not quite Will

$$\sqrt[5]{32y^{10}}\\\\
=\sqrt[5]{32}*\sqrt[5]{y^{10}}\\\\
=32^{1/5}}*y^{10*1/5}\\\\
=2y^2\\\\$$

 Jul 10, 2014
 #1
avatar+561 
+5

5th root (32 y^10)

=32^1/5 * y^5/10

=2 * y^1/2

=2 * sqroot y

I think this is correct, you need to think of root 5 as to the power of 1/5.

 Jul 9, 2014
 #2
avatar+118680 
+10
Best Answer

Almost but not quite Will

$$\sqrt[5]{32y^{10}}\\\\
=\sqrt[5]{32}*\sqrt[5]{y^{10}}\\\\
=32^{1/5}}*y^{10*1/5}\\\\
=2y^2\\\\$$

Melody Jul 10, 2014
 #3
avatar+546 
0

Thank you Will and Melody!

 Jul 11, 2014

3 Online Users

avatar
avatar
avatar