fifth root(32y^10)
Almost but not quite Will
$$\sqrt[5]{32y^{10}}\\\\ =\sqrt[5]{32}*\sqrt[5]{y^{10}}\\\\ =32^{1/5}}*y^{10*1/5}\\\\ =2y^2\\\\$$
5th root (32 y^10)
=32^1/5 * y^5/10
=2 * y^1/2
=2 * sqroot y
I think this is correct, you need to think of root 5 as to the power of 1/5.
Thank you Will and Melody!