I need this fast please

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fifth root(32y^10)

Nataszaa Jul 9, 2014

+118608

+10

Best Answer

Almost but not quite Will

$$\sqrt[5]{32y^{10}}\\\\
=\sqrt[5]{32}*\sqrt[5]{y^{10}}\\\\
=32^{1/5}}*y^{10*1/5}\\\\
=2y^2\\\\$$

Melody Jul 10, 2014

Melody · Answer 1 · 2014-07-10T12:51:00

Almost but not quite Will

$$\sqrt[5]{32y^{10}}\\\\
=\sqrt[5]{32}*\sqrt[5]{y^{10}}\\\\
=32^{1/5}}*y^{10*1/5}\\\\
=2y^2\\\\$$

Will85237 · Answer 2 · 2014-07-09T07:46:14

5th root (32 y^10)

=32^1/5 * y^5/10

=2 * y^1/2

=2 * sqroot y

I think this is correct, you need to think of root 5 as to the power of 1/5.

Nataszaa · Answer 3 · 2014-07-11T11:30:55

Thank you Will and Melody!