i need to calculate the Ka value of a titration. Ka= shift log 10^(-5.2) but i don't know how to put the shift and log in this calculator. A

 

 

shift log 10^(-5.2) 

 

I just put in the input bar as 

log(10^-5.2)=

 

$${log}_{10}\left({{\mathtt{10}}}^{-{\mathtt{5.2}}}\right) = {\mathtt{\,-\,}}{\frac{{\mathtt{26}}}{{\mathtt{5}}}} = -{\mathtt{5.2}}$$

What is the expression you need to evaluate???

 

Remember, for example,   $$\mathbf{\log_{10}(10^{-5.2})\ =\ -5.2}$$