-100 * 2^(0.5y) = -5
Which of the following is the solution of the equation?
-100 * 2^(0.5y) = -5 divide both sides by -100
2^(0.5y) = -5/-100 = 1/20 take the log of both sides
log 2^(0.5y) = log (1/20) and we can write
(0.5y) * log 2 = log (1/20)
y = log(1/20) / (0.5* log 2 ]
y = (1/0.5) * log (1/20) / log 2 reverse the change-of-base theorem
y = 2 * log2 (1/20)