Find the standard form of the equation of the line passing through (4, – 2) and (– 5, 2).
We write the slope intercept form equation first based on the two given points. The slope is -4/9. We now have y=-4/9x+b. We then plug in one of the points to determine b.
y=-4/9x+b
-2=-4/9(4)+b
-2=16/9+b
b=-2/9
So the equation is y=-4/9x-2/9. We then convert it to standard form.
y=-4/9x-2/9
4/9x+y=-2/9
4x+9y=-2