Find the area of the region that lies below the graph of y = 3 - |-x-1| but above the x-axis.
This is the other question: https://web2.0calc.com/questions/help-hw
But this equation is different because the absolute value is subtracted instead of added.
By looking at the graph, we can see that the area in question is a triangle. And we can see that....
The x-intercepts are the points (-4, 0) and (2, 0)
The vertex is the point (-1, 3)
base of triangle = 2 - -4 = 6
height of triangle = 3
area of triangle = (1/2)(base)(height) = (1/2)(6)(3) = 9 sq units