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Find the area of the region that lies below the graph of y = 3 - |-x-1| but above the x-axis.

 May 14, 2019
 #1
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This is the other question: https://web2.0calc.com/questions/help-hw

 

But this equation is different because the absolute value is subtracted instead of added.

 

 

By looking at the graph, we can see that the area in question is a triangle. And we can see that....

 

The x-intercepts are the points  (-4, 0)  and  (2, 0)

 

The vertex is the point  (-1, 3)

 

base of triangle  =  2 - -4  =  6

 

height of triangle  =  3

 

area of triangle  =  (1/2)(base)(height)  =  (1/2)(6)(3)  =  9 sq units

 May 14, 2019

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