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Andy and Jimmy collected 370 toy cars altogether. 1/4 of Andy's toy cars was 25 more than 1/5 of Jimmy's toy cars. How many toy cars did Andy collect than Jimmy?

Sep 8, 2021

#1
+1

Let  A  represent the number of toy cars that Andy has.

Let  J  represent the number of toy cars that Jimmy has.

Since the total number that Andy and Jimmy have is 370, we have this equation:

A + J  =  370

"1/4 of Andy's toy cars"  is written as  " 1/4 · A "

"1/5 of Jimmy's toy cars"  is written as " 1/5 · J "

"was 25 more than"  is written as  " =  25 + "

So we now have the equation:  1/4 A  =  25 + 1/5 J.

To get rid of fractions from this equation, multiply the equation by 20:

20 [ 1/4A  =  25 + 1/5 J ]     --->     5A  =  500 + 4J

Rewriting this equation:     5A - 4J  =  500

Putting these two equations together:

A +  J  =  370     --->   multiply by 4   --->     4A + 4J  =  1480

5A - 4J  =  500                                    --->      5A - 4J  =    500

Adding down the columns:                                 9A         =  1980

Dividing by 9:                                                                A  =  220     (number of Andy's toy cars)

Since the total number of cars is 370, Jimmy has 150 toy cars.

Sep 8, 2021
#2
0

So 220 - 150 = 70 is the answer?

Guest Sep 8, 2021
#3
+1

Andy and Jimmy collected 370 toy cars altogether. 1/4 of Andy's toy cars was 25 more than 1/5 of Jimmy's toy cars. How many toy cars did Andy collect than Jimmy?

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A + J = 370

4(25 + J/5) + J = 370

J = 150

I'll let you figure out the rest. Sep 8, 2021
#4
0

plz respond

KourageKowardlyDog  Sep 8, 2021
#5
0

Yes, that's correct!

jugoslav Guest Sep 8, 2021