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also, are these correct? 

 

 Feb 24, 2019

Best Answer 

 #1
avatar+27844 
+3

For b:   \(\log_5w+\frac{\log_5u}{3}-\frac{\log_5v}{3}\rightarrow \log_5w+\frac{\log_5u/v}{3} \rightarrow \log_5w+\log_5((\frac{u}{v})^{1/3})\rightarrow \log_5(w(\frac{u}{v})^{1/3})\)

 

or you could express this as \(\frac{\log_5(w^3u/v)}{3}\)

 

For e you should have 2x, not just 2.

 Feb 24, 2019
 #1
avatar+27844 
+3
Best Answer

For b:   \(\log_5w+\frac{\log_5u}{3}-\frac{\log_5v}{3}\rightarrow \log_5w+\frac{\log_5u/v}{3} \rightarrow \log_5w+\log_5((\frac{u}{v})^{1/3})\rightarrow \log_5(w(\frac{u}{v})^{1/3})\)

 

or you could express this as \(\frac{\log_5(w^3u/v)}{3}\)

 

For e you should have 2x, not just 2.

Alan Feb 24, 2019

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