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avatar+924 

I think i plug in the values but I am unsure

 Feb 21, 2019
 #1
avatar+100570 
+2

f(x) =  [ 1 + 2x] / x

 

g(x) = 2 + x

 

Look at the top graph....when x = 1...plug this value into the functions and find that  ...f(1) = 3   and g(1) = 3

So....this x value is correct....the graphs intersect at (1, 3)

 

Likewise.....on the graph, when x = -1, plug -1 into both functions and find that....  f(-1) = 1    and g(-1) = 1

So.....this x value is also correct....the graphs also  intersect at (-1,1)

 

So...the x values are

 

x = 1

 

x = -1

 

 

To see why the other graph is incorrect....x = 2 , y = 0 appears to be an intersection point 

But f(2)  = 5/2 = y

And g(2) = 4 =y

So...this can't be correct because the y values are different...and both should be = 0

 

Does this make sense ???

 

cool cool cool

 Feb 21, 2019
 #2
avatar+924 
+1

Yes it all makes sense. thank you smiley

jjennylove  Feb 21, 2019

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