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Find the values of m and n for the Pythagorean triple 48, 55, 73.

 

I also need the work.

 

Thanks so much,

Jeff

 Feb 9, 2019
 #1
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\(55 = m^2 - n^2\\ 48 = 2 m n\\ 73 = m^2 + n^2\)

 

\(55 = 5 \cdot 11 = (m+n)(m-n)\\ m+n=11\\ m-n=5\\ m = 8,~n=3\)

.
 Feb 9, 2019
 #2
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I'm a little confused Rom. How do you tell which of the pythagorean triples correspond to A, B, and C?

 Feb 10, 2019

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