I wanna ask a question, I guess it's easy for most of you but.. a = 8^-2.2^7 b = 4^-3 What is a/b? I tried to solve it and I guess the answe

a  =  8^-2 x 2^7 

Since 8 ^ -2  =  1 / 8^2  =  1/64   and   2^7  =  128,   8^-2 x 2^7  =  128/64  =  2

b  = 4^-3  =  1 / 4^3  =  1/64

a/b  =  (2) / (1/64)  =  2 x (64/1)  =  128

So, a/b = 128,    or, as a ratio:  128/1 

$${\mathtt{a}} = {{\mathtt{8}}}^{{\mathtt{\,-\,}}\left({{\mathtt{2.2}}}^{{\mathtt{7}}}\right)} \Rightarrow {\mathtt{a}} = {\mathtt{0}}$$

$${\mathtt{b}} = {{\mathtt{4}}}^{-{\mathtt{3}}} \Rightarrow {\mathtt{b}} = {\mathtt{0.015\: \!625}}$$

So sorry I meant 8^-2x2^7, not 8^-2.2^7 

whoa wait, ((8^-2)*2^7)/2^6

$${\mathtt{a}} = {\frac{\left(\left({{\mathtt{8}}}^{-{\mathtt{2}}}\right){\mathtt{\,\times\,}}{{\mathtt{2}}}^{{\mathtt{7}}}\right)}{{{\mathtt{2}}}^{{\mathtt{6}}}}} \Rightarrow {\mathtt{a}} = {\mathtt{0.031\: \!25}}$$

Thank you! 

No problem anon!