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I want to find the intercepting point on a linear and quadratic equation 

The equations are 

y=2.6x

y=0.5558x2-2.482x+4.4573

The answers i got were x = 4.534 and x = 0.98 

y= 2.548 and y = 11.7884

2.548 and 0.98 are both right but the higher number on the quadratics are wrong i know because i graphed it.

Please help!

It should be x=8.161 and y = 21.218..........x= 0.98 y = 2.548

 
Guest Jun 12, 2017

Best Answer 

 #1
avatar+75333 
+1

y=2.6x

y=0.5558x^2-2.482x+4.4573

 

Set the y's equal.....and we have

 

2.6x  =  0.5558x^2-2.482x+4.4573     subtract  2.6x from borh sides

 

 0.5558x^2 - 5.082x +4.4573  =  0

 

And the solutions are  

 

x ≈  0.982689      and   x  ≈   8.16089

 

 

 

cool cool cool

CPhill  Jun 12, 2017
Sort: 

1+0 Answers

 #1
avatar+75333 
+1
Best Answer

y=2.6x

y=0.5558x^2-2.482x+4.4573

 

Set the y's equal.....and we have

 

2.6x  =  0.5558x^2-2.482x+4.4573     subtract  2.6x from borh sides

 

 0.5558x^2 - 5.082x +4.4573  =  0

 

And the solutions are  

 

x ≈  0.982689      and   x  ≈   8.16089

 

 

 

cool cool cool

CPhill  Jun 12, 2017

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