I would like some help please ...Solve

Well, in that case, this is your question       R=(mB-t)/k      for B

multiply both sides by k

Rk=mB-t

We now want the lots of B bu themselves so I need to get rid of the -t

the opposite of -t is +t  

SO  I plus t to BOTH sides

Rk+t=mB-t+t

Rk+t=mB

Rk+t=m*B

Now I have to get rid of the m the opposite of *m is  divide by m and a divide is the same as a fraction

$$\\\frac{Rk+t}{m}=\frac{mB}{m}\\\\
\frac{Rk+t}{m}=B\\\\
B=\frac{Rk+t}{m}\\\\$$

OR in other words     B=(Rk+t)/m

without the brackets it is wrong :)

Sorry Chris I should have let you handle it  :))

 R= mB - T / K    add  T/K  to both sides

R + T/K   = mB    divide by m on both sides

[ R + T/K ] / m   = B

And there you go....!!!!

Would this be right?

R= mB - T / K (for B)

T= RK - T / m

=mB - T / m + T

B= RK + T / m

hi Kim,

You are trying to do too many things at once it makes my mind boggle  lol

$$R= mB - \frac{T}{K} \qquad($solve for B$)$$

Firstly is THIS your intended question?    If it is not then you need brackets  

Lol

Here's an image:

R = [ mB - T ] / K   multiply both sides by K

KR  = mB - T      add T to both sides

KR + T  = mB   divide both sides by m

[KR + T ] / m = B 

Oh, my mistake, sorry! I should have shown the image at first when I asked the question :/

Thank you both for your help :)

You are welcome, next time hopefully you will know how to use the brackets correctly.  

No prob, KimLee.....we knew if it wasnt one way it would probably be the other......