I would want to have help on this question

How many sweets does sandra have in the container in the end?

Hello Guest!

$\color{blue}z+p+10=\frac{2}{3}(z+p+10)+z\\ p+10=\frac{2}{3}z+\frac{2}{3}p+\frac{20}{3}\\ \frac{p}{3}=\frac{2z}{3}+\frac{20}{3}$

$p=2z+20$

$\color{blue}z+p+10+30=\frac{3}{4}(z+p+40)+z\\ p+40=\frac{3}{4}z+\frac{3}{4}p+30\\ \frac{p}{4}=\frac{3}{4}z-10$

$p=3z-40$

$2z+20=3z-40$

$z=60$

$p=2z+20$

$p=140$

$140+10+30+60=\color{blue}240\ sweets\\ does\ Sandra\ have\ in\ the\ container\ in\ the\ end.$

  !