Moderators, i know this is much, but i need this, i just got back from my finals and got a 100/126 on my finals, so i got a 88%percent on my onlinehomework, so i need help with these so that i could get 90.

Veteran
Mar 21, 2017

#1**+1 **

y = 4x^2

rsin(theta) = 4r^2cos^2 (theta) divide by r on both sides

sin(theta) = 4r * cos^2(theta)

r = (1/4)sin(theta) / [cos^2 (theta) ]

r = (1/4) sin(theta)/cos(theta) * 1 /cos(theta)

r = (1/ 4) tan(theta) * sec(theta)

Look at the graph, here : https://www.desmos.com/calculator/7uoqlyx4rx

sin^2(w) - cos^2(w) = sin(w) - 1

sin^2(w) - (1 - sin^2(w) ) - sin(w) + 1 = 0

2sin^2(w) - sin(w) = 0 factor out a sin(w)

sin(w) [ 2sin(w) - 1 ] = 0

So either ..... sin(w) = 0 and this happens at 0 and pi .....or....

2sin(w) - 1 = 0 add 1

2sin(w) = 1 divide by 2

sin(w) = 1/2 and this happens at pi/6 and 5pi/6

So the solutions are [ 0, pi/6, 5pi/6 , pi ]

Here's a graph of the solutions......https://www.desmos.com/calculator/c0wjnrrb0u

CPhill
Mar 21, 2017