+280 Moderators, i know this is much, but i need this, i just got back from my finals and got a 100/126 on my finals, so i got a 88%percent on my onlinehomework, so i need help with these so that i could get 90.
+129918 y = 4x^2
rsin(theta) = 4r^2cos^2 (theta) divide by r on both sides
sin(theta) = 4r * cos^2(theta)
r = (1/4)sin(theta) / [cos^2 (theta) ]
r = (1/4) sin(theta)/cos(theta) * 1 /cos(theta)
r = (1/ 4) tan(theta) * sec(theta)
Look at the graph, here : https://www.desmos.com/calculator/7uoqlyx4rx
sin^2(w) - cos^2(w) = sin(w) - 1
sin^2(w) - (1 - sin^2(w) ) - sin(w) + 1 = 0
2sin^2(w) - sin(w) = 0 factor out a sin(w)
sin(w) [ 2sin(w) - 1 ] = 0
So either ..... sin(w) = 0 and this happens at 0 and pi .....or....
2sin(w) - 1 = 0 add 1
2sin(w) = 1 divide by 2
sin(w) = 1/2 and this happens at pi/6 and 5pi/6
So the solutions are [ 0, pi/6, 5pi/6 , pi ]
Here's a graph of the solutions......https://www.desmos.com/calculator/c0wjnrrb0u
