For a certain function f(n), the identity
(2n)/n - (2n)/(n + 1) = f(n) (2n)/n
for all nonnegative integers n. Find f(n).
2n/n = 2
2 - 2n/(n + 1) = f(n) * 2
1 - n/(n + 1) = f(n)
n > or = to 0.
1 - 0 = f(0)
1/2 = f(1)
1/3 = f(2)
1 - 3/(3 + 1) = 1/4 = f(3)
So you can see the pattern, and thus f(n) = 1/(n + 1)
