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If 0 degrees is greater or less than theta greater than 360 degrees, find all values of theta when csc theta equals 2 squared

 Sep 16, 2014

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 #1
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Find θ in the range 0≤θ<360° when csc θ = 22 (or csc θ = 4)

csc is 1/sin, so sin θ = 1/4 

 

θ = sin-1(1/4)

$${\mathtt{theta}} = \underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{sin}}^{\!\!\mathtt{-1}}{\left({\frac{{\mathtt{1}}}{{\mathtt{4}}}}\right)} \Rightarrow {\mathtt{theta}} = {\mathtt{14.477\: \!512\: \!185\: \!93^{\circ}}}$$

θ ≈ 14.5°  This is the value within the first quadrant.

 

sin θ is also positive in the third quadrant, so another approximate value for θ is 180° - 14.5° = 165.5°

 Sep 16, 2014
 #1
avatar+33653 
+5
Best Answer

Find θ in the range 0≤θ<360° when csc θ = 22 (or csc θ = 4)

csc is 1/sin, so sin θ = 1/4 

 

θ = sin-1(1/4)

$${\mathtt{theta}} = \underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{sin}}^{\!\!\mathtt{-1}}{\left({\frac{{\mathtt{1}}}{{\mathtt{4}}}}\right)} \Rightarrow {\mathtt{theta}} = {\mathtt{14.477\: \!512\: \!185\: \!93^{\circ}}}$$

θ ≈ 14.5°  This is the value within the first quadrant.

 

sin θ is also positive in the third quadrant, so another approximate value for θ is 180° - 14.5° = 165.5°

Alan Sep 16, 2014

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