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If 1+12+123+1234+12345+123456+1234567+12345678 is congruent to n modulo 9, where $0\le n<9$, what is the value of n?

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If 1+12+123+1234+12345+123456+1234567+12345678 is congruent to n modulo 9, where $0\le n<9$, what is the value of n?

 Oct 31, 2020

2+0 Answers

 #1
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(1 + 12 + 123 + 1234 + 12345 + 123456 + 1234567 + 12345678) mod 9 = 3

 

n = 3

 Oct 31, 2020
 #2
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-1

incorrect... sorry... but thanks!

 Oct 31, 2020

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