If 10 people are seated in a random manner in a row containing 20 seats, what is the probability thatno two people will occupy adjacent seats?
+394 The total number of ways 10 people can occupy 20 seats (in a row) is nCr(20,10) (184756).
There are only 2 ways 10 people can occupy 20 seats (in a row) that have no adjacent person.This is can be defined by odd or even seats (1,3,5 . . . or 2,4,6 . . .).
Of the 184756 combinations, only two allow for the condition specified and this gives a probability:
Derived from nCr(20,10)/2 =92378
(1/92378) = 0.0000108250882245
_7UP_
+394 The total number of ways 10 people can occupy 20 seats (in a row) is nCr(20,10) (184756).
There are only 2 ways 10 people can occupy 20 seats (in a row) that have no adjacent person.This is can be defined by odd or even seats (1,3,5 . . . or 2,4,6 . . .).
Of the 184756 combinations, only two allow for the condition specified and this gives a probability:
Derived from nCr(20,10)/2 =92378
(1/92378) = 0.0000108250882245
_7UP_
