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If 2^x=7, what is the value of 2^2x?

 Oct 29, 2018
 #1
avatar+17209 
+1

Log 2^x = log 7

x log 2 = log 7

x = log7/log2 = 2.8074

2^(2x) = 2^(2*2.8074) = 49

 Oct 29, 2018
 #2
avatar+98044 
+1

Thanks, EP....here's a slightly easier way

 

2^x  = 7

 

2^(2x) =

 

 [ 2 ^x ] ^2  =

 

7^2   =

 

49

 

cool cool cool

 Oct 30, 2018

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