If 3x-y=12 What is the value of 8x/2y ?
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\(3x-y=12\\ y=3x-12\\ 2y=6x-24\)
\(3x-y=12\\ x=\dfrac{y+12}{3}\\ 8x=\dfrac{8y+96}{3}\)
\(\dfrac{8x}{2y}=\dfrac{8y+96}{3(6x-24)}=\dfrac{4(3x-12+12)}{9(x-4)}=\color{blue}\dfrac{12x}{9x-36}\)
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