if 3y + 5 = -10 what would y be?

3y + 5 = -10

3y = -10 - 5 ---  Shift 5 to right side of equal which changes it from a positive 5 to a negative 5
3y = -15 ---  -10 - 5 = -15

 y = -5 ---  Since both sides are divisible by 3, we divide them by 3 to simplify the answer. 3y / 3 = y & -15 / 3 = -5

\(3y+5=-10 \)

\(3y+5-5=-10-5\)

\(3y=-15\)

\(\frac{3y}{3}=\frac{-15}{3 }\)

\(y=-5\)

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