If 64.15g of HCl were produced from 2.07g of H2 and an excess of Cl2 according to the rreaction
H2 + Cl2 ---------> 2HCl
What was the percentage yield of HCl?
Please show the solution so I can understand.
+561 Moles of HCl produced is:
mass/atomic mass
=64.15/(35.5+1)
=1.76mol
Moles of H2 used is:
mass/atomic mass
=2.07/1
=2.07mol
By dividing the the moles of H2 used by the moles of HCl created, we get the percentage yield of the reaction:
1.76/2.07
=0.85
=85%
Note that I may have rounded too much, you might need to use more accurate values for the atomic masses.
DISCLAIMER: I have never calculated percentage yield in chemistry so I might be wrong.
