If (64/729)^x = 243/32 find the value of X
(64/729)^x = 243/32
(64/ 729)^x = 3^5 / 2^5
( 2^6 / 3^6 )^x = ( 2^5 / 3^5) ^(-1)
2^(6x) / 3^(6x) = 2^(-5) / 3^(-5)
(2/3)^(6x) = (2/3)^(-5) → 6x = -5 → x = - 5 / 6