Hello,
\(A+B+0C=15\)
\(0A+B+C=20\)
\(A+0B+C=25\)
Add all three
\(2A+2B+2C=60\)
Factor 2
\(2(A+B+C)=60\)
Divide by 2
\(A+B+C=30\)
A+B=15 10+5=15
B+C=20 5+15=20
C+A=25 15+10=25
A+B+C = 30
a+b=15
b+c=20
c+a=25
then add,
a+c=25
b+c=20
a+b=15
2a+2b+2c=60
divide by 2 on both sides and you get
a+b+c=30
just add all equations. You will get 2A+2B+2C=60
so A+B+C=60/2 = 30