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if a track is 12566 feet (360 degrees) around, how many degrees would 10000 feet around the track be

Guest Mar 26, 2015

Best Answer 

 #1
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(10000/12566) x 360°  = about 286.49°

 

  

CPhill  Mar 26, 2015
 #1
avatar+86869 
+5
Best Answer

(10000/12566) x 360°  = about 286.49°

 

  

CPhill  Mar 26, 2015

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