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Why or why not??

(for homework help is appreciated!)

 Nov 28, 2016
edited by Guest  Nov 28, 2016
edited by Guest  Nov 28, 2016
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Lets think about it ...

 

\(3^{-2}=\frac{1}{3^2}\\~\\ 3^{-1/2}=\frac{1}{\sqrt3}\\~\\ 0^{anything\; except\: 0} =0\\~\\ (-3)^{-2}=\frac{1}{(-3)^2}\\ (-3)^{-1/2}=not\;a\;real\;number\\ (-3)^{-3}=\frac{1}{(-3)^3}=?\\ \)

 

So what do your think?

 Nov 28, 2016

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