So, I am trying to solve this problem but it is quite weird. I start out with labeling that angle B is 39 degrees and arc PS is 116 degrees. I am not to sure what is the relationship between angle B and arc AP. All I know is that the arc AP and triangle BAP share segment AP. That means that the measure of arc AP is twice the measure of angle B which is 78. To find arc AS we subtract 360-78-116 which equals 166. But 166 is not the answer. I know that arc AP is probably not twice angle B. How do you solve this problem? Also, if you are going to refer me to this page: https://web2.0calc.com/questions/pls-help-due-tmrow_7 then I am going to tell you that CPhill got the wrong answer. PLEASE HELP!
+128406 I just made a typo in the original problem....I used 38 instead of 39.....here is the corrected answer :
3)
If angle B = 39 degrees and arc PS = 116 degrees, find the degree measure of arc AS.
Angle B = (1/2) ( arc AS - arc AP)
39 = (1/2) (arc AS - arc AP)
78 = arc AS - arc AP (1)
And
arc AS + arc AP + arc PS = 360
arc AS + arc AP + 116 = 360
arc AS + arc AP = 244 (2)
Add (1) and (2)
arc AS - arc AP = 78
arc AS + arc AP = 244
2 arc AS = 322 divide by 2
arc AS = 161°
