#1**+1 **

The least amount of wrapping paper needed is the surface area of the cube.

A cube has six square faces, and each face is the same size. So...

surface area of cube = 6(area of square face)

And area of square face = (side length)^{2}

surface area of cube = 6(side length)^{2}

The problem tells us that the cube is 11 cm long, so the side length = 11 cm

surface area of cube = 6( 11 cm )^{2}

surface area of cube = 6( 121 cm^{2} )

surface area of cube = 726 cm^{2}

least amount of wrapping paper needed = 726 cm^{2}

hectictar Apr 26, 2018