If a,b,c are positive integers less than 13 such that
2ab+bc+ca≡0(mod13)ab+2bc+ca≡3abc(mod13)ab+bc+2ca≡8abc(mod13)
then determine the remainder when a+b+c is divided by 13.
Answer with solution will be appreciated
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Notice that if b = 2a and c = 3a the left hand side of the first equation becomes 4a2 + 6a2 + 3a2 = 13a2
In other words it is a multiple of 13 and hence satisfies the first equation.
For this situation, if a, b and c are all positive integers less than 13, then a can only be one of 1, 2, 3 or 4.
Trying these in turn we find that only a = 3 (hence b = 6 and c = 9) satisfy the second and third equations.
Hence a + b + c = 5 mod(13)