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if B= L/(4piD^2) what would be the formula to find D?

 Mar 15, 2015

Best Answer 

 #1
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solve for D

B = L/(4$${\mathtt{\pi}}$$$${{\mathtt{D}}}^{{\mathtt{2}}}$$)

B(4$${\mathtt{\pi}}$$$${{\mathtt{D}}}^{{\mathtt{2}}}$$) = L

(4$${\mathtt{\pi}}$$$${{\mathtt{D}}}^{{\mathtt{2}}}$$) = L/B

$${{\mathtt{D}}}^{{\mathtt{2}}}$$ = L/(B*4pi)

D = $${\sqrt{{\frac{{\mathtt{L}}}{\left({\mathtt{4}}{\mathtt{\,\times\,}}{\mathtt{piB}}\right)}}}}$$

 Mar 15, 2015
 #1
avatar
+5
Best Answer

solve for D

B = L/(4$${\mathtt{\pi}}$$$${{\mathtt{D}}}^{{\mathtt{2}}}$$)

B(4$${\mathtt{\pi}}$$$${{\mathtt{D}}}^{{\mathtt{2}}}$$) = L

(4$${\mathtt{\pi}}$$$${{\mathtt{D}}}^{{\mathtt{2}}}$$) = L/B

$${{\mathtt{D}}}^{{\mathtt{2}}}$$ = L/(B*4pi)

D = $${\sqrt{{\frac{{\mathtt{L}}}{\left({\mathtt{4}}{\mathtt{\,\times\,}}{\mathtt{piB}}\right)}}}}$$

Guest Mar 15, 2015

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