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If c=12, m angle A=80, and m angle c=40, find a

 Apr 15, 2015

Best Answer 

 #1
avatar+26400 
+5

If c=12, m angle A=80, and m angle c=40, find a

 

The sine rule

 

We can use the sine rule to find the size of an angle or length of a side.

 

 

 

 

The sine rule is:

a over sinA = b over sinB = c over sinC or sinA over a = sinB over b = sinC over c

$$\small{\text{
Here we have:
$
\boxed{
\dfrac{ \sin{(C)} }{c}= \dfrac{ \sin{(A)} }{a}
}
$}} \\\\
a\cdot \sin{(C)} = c\cdot \sin{(A)} \\\\
a = c\cdot \dfrac{\sin{(A)} }{ \sin{(C)} }\\\\
a = 12\cdot\dfrac{\sin{(80\ensurement{^{\circ}})} }{ \sin{(40\ensurement{^{\circ}})} }\\\\
a = 12\cdot\dfrac{ 0.98480775301}{ 0.64278760969}\\\\
a = 12\cdot 1.53208888624\\\\
a = 18.3850666349$$

 

 Apr 16, 2015
 #1
avatar+26400 
+5
Best Answer

If c=12, m angle A=80, and m angle c=40, find a

 

The sine rule

 

We can use the sine rule to find the size of an angle or length of a side.

 

 

 

 

The sine rule is:

a over sinA = b over sinB = c over sinC or sinA over a = sinB over b = sinC over c

$$\small{\text{
Here we have:
$
\boxed{
\dfrac{ \sin{(C)} }{c}= \dfrac{ \sin{(A)} }{a}
}
$}} \\\\
a\cdot \sin{(C)} = c\cdot \sin{(A)} \\\\
a = c\cdot \dfrac{\sin{(A)} }{ \sin{(C)} }\\\\
a = 12\cdot\dfrac{\sin{(80\ensurement{^{\circ}})} }{ \sin{(40\ensurement{^{\circ}})} }\\\\
a = 12\cdot\dfrac{ 0.98480775301}{ 0.64278760969}\\\\
a = 12\cdot 1.53208888624\\\\
a = 18.3850666349$$

 

heureka Apr 16, 2015
 #2
avatar+118723 
0

Very nice Heureka :)

 Apr 16, 2015

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