If Cot of theta is sqrt(3). I'm having trouble finding Sin. I assume that it is 1/sqrt(3) or 1*sqrt(3)/3. But that doesn't seem to be an answer. I'm taking a College Trig class over the summer. Plz help. Thank you.

Think of a right-angled triangle in which the adjacent side to theta is √3 and the opposite is 1 (so cot(theta) = √3/1 = √3).

The hypotenuse is then: √(3+1) = √4 = 2.

This means sin(theta) = opposite/hypotenuse = 1/2

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