#1**0 **

This is a little tricky !!!......we want to first get x by itself

y = (2x-1)/(x+2) multiply both sides by x + 2

y(x +2) = 2x - 1

xy + 2y = 2x - 1

xy - 2x = -2y - 1

x ( y - 2) = -(2y + 1 ) divide both sides by y - 2

x = -(2y + 1) / (y - 2) .......now ...."swap" x and y

y = - (2x + 1) / ( x - 2) and for y, write f^{-1} (x)

f^{-1} (x ) = - (2x + 1) / (x - 2)

CPhill
Feb 26, 2017