+0  
 
0
154
1
avatar+272 

If f(x)=\sqrt{x-3}, what is the smallest real number x in the domain of f(f(x))?

WhichWitchIsWhich  Nov 2, 2017
 #1
avatar+86890 
+2

f (f(x) )    =

 

√  [ √ ( x - 3) - 3 ]

 

Since     √ ( x - 3) - 3    must be >=  0, set this to 0

 

Add 3 to both sides

 

√ ( x - 3)    =  3       square both sides

 

x - 3  =  9

 

x =  12

 

So...the domain  is  [12, inf )

 

 

cool cool cool

CPhill  Nov 2, 2017

10 Online Users

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.