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# If $f(x) = x^2 - 3x + 4$, find the value of $f(\sqrt3 - \sqrt2)$.

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If $$f(x) = x^2 - 3x + 4$$, find the value of $$f(\sqrt3 - \sqrt2)$$

Guest Jul 12, 2017

### Best Answer

#1
+91479
+3

If , find the value of

f(x) = x^2 - 3x + 4

$$f(\sqrt3 - \sqrt2)\\ =(\sqrt3 - \sqrt2)^2-3(\sqrt3 - \sqrt2)+4\\ =3-2\sqrt6+2-3\sqrt3 +3\sqrt2+4\\ =9-2\sqrt6-3\sqrt3 +3\sqrt2\\$$

Melody  Jul 12, 2017
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### 3+0 Answers

#1
+91479
+3
Best Answer

If , find the value of

f(x) = x^2 - 3x + 4

$$f(\sqrt3 - \sqrt2)\\ =(\sqrt3 - \sqrt2)^2-3(\sqrt3 - \sqrt2)+4\\ =3-2\sqrt6+2-3\sqrt3 +3\sqrt2+4\\ =9-2\sqrt6-3\sqrt3 +3\sqrt2\\$$

Melody  Jul 12, 2017
#2
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Is there any way u can further simplify that answer

Guest Jul 12, 2017
#3
+91479
+1

This cannot be simplified any further.

Melody  Jul 12, 2017

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