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If f(x)=x^5-1/1, find f^-1(-31/96).

Guest Jul 17, 2018
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If f(x)=x^5-1/1, find f^-1(-31/96).

 

1/1=1

 

\(let\;\; y=f(x)\\ y=x^5-1\\ if\; y=-31/96 \;\;find\;\;x\\ \frac{-31}{96}+1=x^5\\ \frac{65}{96}=x^5\\ x=\sqrt[5]{\frac{65}{96}} \)

 

(65/96)^(1/5) = 0.9249716558029023

 

Here is the graph

 

Melody  Jul 17, 2018

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