Since both 2 and 3 are prime numbers, we should find the prime factorization of \(12^2\cdot18^3\). So:
12 = 2*2*3
12=2*2*3
18=2*3*3
18=2*3*3
18=2*3*3
As you see, we have 8 3's and 7 2'. So, 8+7 is \(\boxed{15}\)
:)
122 * 183
(2*2*3)2 * (2*3*3)3
22+2+3 * 32+3+3
27 * 38 now you can see x and y (as ilorty found)