if i am given two sides of a triangle with the angle in between how do i find the third angle
if i am given two sides of a triangle with the angle in between how do i find the third angle
1. Example: Given b,c and $$\angle CAB$$ (A) between:
$$\tan{(B)} = \dfrac{ b\cdot \sin{(A)} }{ c-b\cdot \cos{(A)}}\qquad
\tan{(C)} = \dfrac{ c\cdot \sin{(A)} }{ b-c\cdot \cos{(A)}}$$
cycle:
2. Example: Given c,a and $$\angle ABC$$ (B) between:
$$\tan{(C)} = \dfrac{ c\cdot \sin{(B)} }{ a-c\cdot \cos{(B)}}\qquad
\tan{(A)} = \dfrac{ a\cdot \sin{(B)} }{ c-a\cdot \cos{(B)}}$$
cycle:
3. Example: Given a,b and $$\angle BCA$$ (C) between:
$$\tan{(A)} = \dfrac{ a\cdot \sin{(C)} }{ b-a\cdot \cos{(C)}}\qquad
\tan{(B)} = \dfrac{ b\cdot \sin{(C)} }{ a-b\cdot \cos{(C)}}$$
if i am given two sides of a triangle with the angle in between how do i find the third angle
1. Example: Given b,c and $$\angle CAB$$ (A) between:
$$\tan{(B)} = \dfrac{ b\cdot \sin{(A)} }{ c-b\cdot \cos{(A)}}\qquad
\tan{(C)} = \dfrac{ c\cdot \sin{(A)} }{ b-c\cdot \cos{(A)}}$$
cycle:
2. Example: Given c,a and $$\angle ABC$$ (B) between:
$$\tan{(C)} = \dfrac{ c\cdot \sin{(B)} }{ a-c\cdot \cos{(B)}}\qquad
\tan{(A)} = \dfrac{ a\cdot \sin{(B)} }{ c-a\cdot \cos{(B)}}$$
cycle:
3. Example: Given a,b and $$\angle BCA$$ (C) between:
$$\tan{(A)} = \dfrac{ a\cdot \sin{(C)} }{ b-a\cdot \cos{(C)}}\qquad
\tan{(B)} = \dfrac{ b\cdot \sin{(C)} }{ a-b\cdot \cos{(C)}}$$