if i am given two sides of a triangle with the angle in between how do i find the third angle

if i am given two sides of a triangle with the angle in between how do i find the third angle

1. Example: Given b,c and   $$\angle CAB$$   (A) between:

$$\tan{(B)} = \dfrac{ b\cdot \sin{(A)} }{ c-b\cdot \cos{(A)}}\qquad \tan{(C)} = \dfrac{ c\cdot \sin{(A)} }{ b-c\cdot \cos{(A)}}$$

cycle:

2. Example: Given c,a and   $$\angle ABC$$   (B) between:

$$\tan{(C)} = \dfrac{ c\cdot \sin{(B)} }{ a-c\cdot \cos{(B)}}\qquad \tan{(A)} = \dfrac{ a\cdot \sin{(B)} }{ c-a\cdot \cos{(B)}}$$

cycle:

3. Example: Given a,b and   $$\angle BCA$$   (C) between:

$$\tan{(A)} = \dfrac{ a\cdot \sin{(C)} }{ b-a\cdot \cos{(C)}}\qquad \tan{(B)} = \dfrac{ b\cdot \sin{(C)} }{ a-b\cdot \cos{(C)}}$$