If (k +2)(x^2 + y^2 ) ≥ 2(x + y)^2 holds for all real numbers x and y, then the minimum possible value of k is

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141

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thanks.

Guest Oct 12, 2022

edited by Guest Oct 12, 2022

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1⁺⁰ Answers

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The smallest possible value of k is 2.

Guest Oct 12, 2022

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