+0  
 
0
559
1
avatar

if lga=1/7lgb-lgc then what is a=?

 Oct 16, 2016
 #1
avatar
0

Solve for a:
7 (log(a)+log(c)) = log(b)

Divide both sides by 7:
log(a)+log(c) = (log(b))/7

Subtract log(c) from both sides:
log(a) = (log(b))/7-log(c)

(log(b))/7-log(c) = log(b^(1/7))+log(1/c) = log(b^(1/7))+log(1/c) = log(b^(1/7)/c):
log(a) = log(b^(1/7)/c)

Cancel logarithms by taking exp of both sides:
Answer: |a = b^(1/7)/c

 Oct 16, 2016

1 Online Users

avatar