If P=210e^.0069*20
=210e^0.138
=210 * 1.148
=241.1 (million)
How do they get: e is approx. 2.718?
+129842 "e" can be generated by this sum
∞
∑ (1 / n! ) ≈ e
n = 0
For example.......the first ten terms of this sum is given by :
1/0! + 1/1! + 1/2! + 1/3! + 1/4! + 1/5! + 1/6! + 1/7! + 1/8! +1/9! ≈ 2.718281525573192239858906
Of course........the more terms, the better the approximation...........
If P=210e^.0069*20
P=210.e^.0069*20
P=210.(1.006924*20)
P=210. 20.138478
P=402.76956. This is the correct answer the way you have written down. If it were: 210e^(.0069*20), then the right answer would be:241.0748655......etc.
Don't understand your last question! How do you derive e?, you mean?
