If sin of theta is 3/5 then tan theta =?
sin(theta) = 3/5 ( opposite side over hypotenuse )
tan(theta) = 3/x ( opposite side over adjacent side )
Answer:> tan(theta) = 3/4
$${\mathtt{x}} = {\sqrt{{{\mathtt{5}}}^{{\mathtt{2}}}{\mathtt{\,-\,}}{{\mathtt{3}}}^{{\mathtt{2}}}}}$$
$${\mathtt{x}} = {\mathtt{4}}$$
If sin of theta is 3/5 then tan theta =?
sin(theta) = 3/5 ( opposite side over hypotenuse )
tan(theta) = 3/x ( opposite side over adjacent side )
Answer:> tan(theta) = 3/4
$${\mathtt{x}} = {\sqrt{{{\mathtt{5}}}^{{\mathtt{2}}}{\mathtt{\,-\,}}{{\mathtt{3}}}^{{\mathtt{2}}}}}$$
$${\mathtt{x}} = {\mathtt{4}}$$