if sin x=.76, what is cos?

$$\sin^2(x)+\cos^2(x)=1$$

$$\cos(x)=\sqrt{1-\sin^2(x)}$$

$$\cos(x)=\sqrt{1-(0.76)^2}$$

$${\sqrt{{\mathtt{1}}{\mathtt{\,-\,}}{\left({\mathtt{0.76}}\right)}^{{\mathtt{2}}}}} = {\mathtt{0.649\: \!923\: \!072\: \!370\: \!876\: \!8}}$$

$$\cos(x) \approx 0.65$$

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$$\sin^2(x)+\cos^2(x)=1$$

$$\cos(x)=\sqrt{1-\sin^2(x)}$$

$$\cos(x)=\sqrt{1-(0.76)^2}$$

$${\sqrt{{\mathtt{1}}{\mathtt{\,-\,}}{\left({\mathtt{0.76}}\right)}^{{\mathtt{2}}}}} = {\mathtt{0.649\: \!923\: \!072\: \!370\: \!876\: \!8}}$$

$$\cos(x) \approx 0.65$$

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